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Mathematics 16 Online
jagr2713 (jagr2713):

Medal And Fan

jagr2713 (jagr2713):

Take the month you were born in. Multiply it by 4, add 13, multiply by 25, subtract 200, add the day you were born, multiply by 2, subtract 40, multiply by 50, add the last two digits of your birth year, subtract 10500…. viola! Your birth date! Impress your friends! Now, use your birthday for some more math fun. You can locate graph paper here. Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below. Using complete sentences, explain how to convert your birthday function into standard form. Graph your function. Include your graph below. Using complete sentences, explain how to find the average rate of change for f(x) from x = 4 to x = 7.

jagr2713 (jagr2713):

@ganeshie8 @Hero @radar @SolomonZelman

jagr2713 (jagr2713):

@sasogeek

jagr2713 (jagr2713):

what

jagr2713 (jagr2713):

@Samsonite16

jagr2713 (jagr2713):

@zepdrix

jagr2713 (jagr2713):

@KlOwNlOvE

OpenStudy (anonymous):

theres someone in havent seen in awhile

jagr2713 (jagr2713):

lol got busy and didnt feel like coming here lol

OpenStudy (anonymous):

:O didn't feel like psh

jagr2713 (jagr2713):

lol can u help?

OpenStudy (anonymous):

i can try not really understanding what it's saying

jagr2713 (jagr2713):

read it and i think you use this formula

OpenStudy (anonymous):

whats the question lol read 2 or 3

OpenStudy (anonymous):

create a function, explain from function to standard, graph, and rate of change?

jagr2713 (jagr2713):

igtg soon can we speed this up and so f(x)=8x+12

OpenStudy (anonymous):

they want you to know what quadratic function, f(x), in vertex form. means it means the equation looks like this: f(x)=a(x−h)2+k they want you to replace the letters "a", "h", and "k" with numbers (based on your birthday) except for "a". The a should be between 4 and –4,

OpenStudy (anonymous):

\[f(x)=a(x-h)^{2}+k\]

OpenStudy (anonymous):

h is your birth month k is your birth day

jagr2713 (jagr2713):

aug 12 my birthday which was tuesday :DD

OpenStudy (anonymous):

8/12

OpenStudy (anonymous):

pick a number between 4 and -4

jagr2713 (jagr2713):

2 igtg in like 3mins can we speed this up

OpenStudy (anonymous):

oh and happy bday btw

jagr2713 (jagr2713):

ty

OpenStudy (anonymous):

this will take longer than 3 minutes to explain being theres multiple parts to the question

jagr2713 (jagr2713):

can u just give the answer i will figure it out later

OpenStudy (anonymous):

\[f(x)=2(x-12^{2})+8\]

OpenStudy (anonymous):

i dont know the answer myself i im reading while doing this and i dont even have all this information that will be your function tho

OpenStudy (anonymous):

part 1 is done now we need to convert that to standard form which means expanding (x-12)^2

jagr2713 (jagr2713):

so whats the answer for part 1

OpenStudy (anonymous):

(x-12)(x-12) x^2-12x -12x+144 so standard form is \[f(x)=2(x^2-24x+144)+8\]

OpenStudy (anonymous):

part 1 is \[f(x)=2(x-12)^2+8\]

jagr2713 (jagr2713):

oh ok i understand

OpenStudy (anonymous):

part 2 will be the next equation i gave you

jagr2713 (jagr2713):

yea i get that

OpenStudy (anonymous):

now we need to graph this can you do that on your own?

jagr2713 (jagr2713):

not really

OpenStudy (anonymous):

this is what i got on a quadratiic function calculator

OpenStudy (anonymous):

now for part 4 \[f(x)=\frac{ 4-7 }{ 4 }×100\]

OpenStudy (anonymous):

\[f(x)=\frac{ -3 }{ 4 }×1000\]

OpenStudy (anonymous):

\[f(x)=-.75×100\]

OpenStudy (anonymous):

\[f(x)=-75%\]

jagr2713 (jagr2713):

it told me to graph

OpenStudy (anonymous):

i posted a screenshot of the graph i got

jagr2713 (jagr2713):

i cant send that let me give u a graph

jagr2713 (jagr2713):

http://prntscr.com/4cv0h8

jagr2713 (jagr2713):

u there

OpenStudy (anonymous):

yeah graph suck but http://prntscr.com/4cv3b3

jagr2713 (jagr2713):

send another one ?

jagr2713 (jagr2713):

@KlOwNlOvE

jagr2713 (jagr2713):

jagr2713 (jagr2713):

there

OpenStudy (anonymous):

http://prntscr.com/4cv7h5

jagr2713 (jagr2713):

dude just give me the points to plot and i will do it

jagr2713 (jagr2713):

@KlOwNlOvE

jagr2713 (jagr2713):

please help man i really gtg soon

OpenStudy (anonymous):

.6x^2 .3x .9Y (-.3,.9) (0,9)

jagr2713 (jagr2713):

what isnt it like 5 points to plot

jagr2713 (jagr2713):

ok skip that part lets do number 4

jagr2713 (jagr2713):

@KlOwNlOvE

OpenStudy (anonymous):

#3 is confusing me very so #4 rate of increase from 4-7 \[rateofincrease=\frac{ new number-old number }{old price }\]

OpenStudy (anonymous):

\[\frac{ 7-4 }{ 4 }\]

OpenStudy (anonymous):

\[\frac{ 3 }{ 4 }\]

OpenStudy (anonymous):

divide numorator by denominator \[3\div4=.75\] to get the percent of increase we multiply by 100 \[.75*100=75\] 75%

jagr2713 (jagr2713):

thx

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