Question

Find \(\color{red}{x}\).

\(\color{green}{y^2 + 2y + 1 = 0}\)

Answer 1

I am not god at math, as you have seen many times before, but maybe I can try ....

\(\normalsize\color{black}{y^2+2x+1=0}\) is the equation for a parabola opening to the right.\(\LARGE\color{white}{ \rm │ }\)

\(\normalsize\color{black}{x=y^2+2x+1}\)\(\LARGE\color{white}{ \rm │ }\)
\(\normalsize\color{black}{x=(y+1)^2}\)\(\LARGE\color{white}{ \rm │ }\)
\(\normalsize\color{black}{x=1(y+1)^2+0}\)\(\LARGE\color{white}{ \rm │ }\)

All I can say is x in terms of y, x=(y+1)²

Answer 2

What??

Answer 3

nvm.... I knew it will be bad

Answer 4

Have I typed the question right or haven't you seen the question with your eyes?

Answer 5

the letter in red is x

Answer 6

i was going to say same thing :P

Answer 7

@sauravshakya has found it.. Good...

Answer 8

odd

Answer 9

@hartnn sorry, saurav was somewhat faster than you in finding that... :)

Answer 10

the question should be solve for x

Answer 11

It is not a question @No.name

Answer 12

The real question is coming now.. :)

Answer 13

bye

Answer 14

Bye?? Why???
Where you are going??? :) You are on OS already and will be. :)

Answer 15

Wow!!! Awesome question!

Answer 16

Yeah I know like you.. :) Thank you thank you.. :P

Answer 17

Pshshhsh....I'm not awsomexD!

Answer 18

Today you know what is common in we both??

Answer 19

I don't wanna know:)

Answer 20

Okay, you are not but my joke is.. :)

Answer 21

\[\Huge Expand 1\]

Answer 22

Expand 1??

Answer 23

Are you alright @No.name ??

Answer 24

yes

Answer 25

Does not seem to be.. :)