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Mathematics 21 Online
OpenStudy (anonymous):

Can someone help me with a couple of questions (if you have some time) thank you!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

@bradely

OpenStudy (kainui):

What's your question? I see your assignment, but what's your question about the assignment?

OpenStudy (anonymous):

Im just all confused about how to set it up so I can solve it

OpenStudy (kainui):

Well, let's focus on one problem at a time. Tell me in your own words what you think the first one is trying to say, or what it's talking about.

OpenStudy (anonymous):

I think its trying to have me figure out the relationship and how it changes each minute to the cost per minute.

OpenStudy (kainui):

Yeah, perfect. So how do you calculate the change in price relative to the change in time? If you are going 60 miles per hour, then for every 60 miles that you have gone (change in distance) then you have spent 1 hour (change of 1 hour). So how do we determine change? Well if I walk from 20 feet away to 24 feet away, then what's the change of distance? Obviously it's 4, right? But what was the math we did secretly without thinking about it? We just took the larger amount and subtracted the smaller amount to find the change. So 24-20=4. Similarly, to find the change between each of the two points, just subtract the higher price from the lower price and subtract the higher time from the lower time. Then divide one by the other just like when you think of miles per hour, think of price per minute instead.

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