Question

Can someone check my work please.

Answer 1

I'm about to post it

Answer 2

Part A: Explain why we do not measure the rate at which a sprinkler waters a lawn in cubic feet per minute? In your explanation, use reasoning based on appropriate units to model this situation. (5 points)

Part B: What are the two quantities that should be measured to find the rate at which a sprinkler waters a lawn? Explain how the rate can be determined. (5 points)

ESSAY SUBMISSION
Part A:
The reason why you wouldn't measure the rate at which a sprinkler waters a lawn in cubic feet per minute is you aren't trying to fill a 3 dimensional space. The term cubic refers to 3, 3 dimensions. You use the term cubic when you're measuring volume. In this case we are measuring the rate at which water is sprayed out onto a 2 dimensional surface. A better way to announce this ratio could be: feet per minute, instead of cubic feet per minute.
For example, let's say that a 5 by 5 area of the lawn is sprinkled with water every minute. That's a ratio of 5 squared feet per minute.

Part B:
The two quantities that should be measured to find the rate at which a sprinkler waters a lawn are, squared feet and minutes. x squared feet per minute.
Let's make a real life scenario out of this expression...
Let's say that the sprinkler sprays water in a semi circle. The radius of this semi circle measures 6 feet. Now let's find the area of the semi circle.
A= πr [A= (3.14)(r)]
A= (3.14)(6)
A= 18.84
So, the area of the semi circle is 18.84 feet. Now to form the ratio...
We know that the sprinkler is able to cover an area of 18.84 feet in 1 minute, so let's make this our ratio.
Every 1 minute(s) the sprinkler waters 18.84 feet of lawn.
18.84 feet per 1 minute.

Answer 3

"A better way to announce this ratio could be: feet per minute, instead of cubic feet per minute." should be:
A better way to announce this ratio could be: SQUARE feet per minute, instead of cubic feet per minute.

Answer 4

Oh yes, That's very true. I wonder if my teacher will catch that. But I completely understand you. Thank you :)

Answer 5

^your teacher will definitely catch that. That was a major part of the problem :P

Answer 6

Area of a circle = \(\pi r^2\)
Area of a semi-circle = \(\frac 12\pi r^2 \frac 12*\pi*6^2 = 18*\pi = 56.55\) ft^2 /min

Answer 7

Your final answer should also be in terms of square feet per minute. I believe the whole point of this assignment is to antiquate you with units.

Also aum has caught another error, in that you used the circumference equation instead of using the area equation.