Solve triangle XYZ if m
I believe this uses the law of sines.
All triangle add up to 180, so 39 + 88 + x = 180 solve for x
yeap... pretty much.. notice you have angle Y and side y
Select one: a. x= 53°, y= 88°, z= 39°, x ≈ 57, y = 70, and z ≈ 44.1 b. x = 53°, y= 88°, z= 39°, x ≈ 55.9, y = 70, and z ≈ 45 c. x= 53°, y = 88°, z= 39°, x ≈ 44, y = 70, and z ≈ 56 d. x = 53°, y = 88°, z = 39°, x ≈ 55.9, y = 70, and z ≈ 44.1
This is what it gives for the answers.
This is a tricky one, drawing it out might help you solve it.
\(\bf \cfrac{sin(Z)}{z}=\cfrac{sin(Y)}{y}\implies y=?\)
This guys smarter listen to him >.>
haemm actually we have y so \(\bf \cfrac{sin(Z)}{z}=\cfrac{sin(Y)}{y}\implies z=?\)
Im confused. I entered in the info and I dunno how to use what I got.
For the first one with sinz I got 55.38. then for the second I got 38.97.
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well... when solving for "z" what would that give you then?
I dunno would I add the two numbers I got together or what?
well.. you'd want to "solve for z" first.... just a linear simplification and then plug in the numbers
Again I don't know what you mean.
well.. is just two fractions... so you'd just firstly need to solve for "z" \(\bf \cfrac{sin(Z)}{z}=\cfrac{sin(Y)}{y}\implies z=\cfrac{\square ?}{\square ?}\)
So I would put 55.38/38.9 then?
well... ... you'd need to simplify for "z" first
And how would I do that?
hmmm well there seems to be an assumption you should know that you can brush up your simplification though -> https://www.youtube.com/watch?v=n3FbQGGKVfc
I still don't know what I need to simplify.
@BaltM here is reference to help with learning how to use law of sines http://en.wikipedia.org/wiki/Law_of_sines#Examples
Thanks. That's all I needed to know.
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