Question

http://prntscr.com/4d9057

Answer 1

@JoannaBlackwelder

Answer 2

@aum

Answer 3

Exactly the same procedure as the past few problems.

Multiply top and bottom by \(4 + \sqrt{6x}\) and simplify.

When multiplying the denominator make use of the identity:
\((a+b)(a-b)= a^2-b^2\).

Answer 4

ok after?

Answer 5

D?

Answer 6

Try again but show the work so it will be easier to correct the mistake.

Answer 7

k

Answer 8

\[4/4-\sqrt{6x}*4/4=\sqrt{6x}\] RIGHT?

Answer 9

oops

Answer 10

i mean \[4/4-\sqrt{6x}*4/4+\sqrt{6x}\]

Answer 11

\[
\frac{4}{4-\sqrt{6x}} = \frac{4}{4-\sqrt{6x}} * \frac{4+\sqrt{6x}}{4+\sqrt{6x}} =
\frac{4(4+\sqrt{6x})}{4^2-\sqrt{6x}^2} = \frac{4(4+\sqrt{6x})}{16-6x} = \\
\frac{4(4+\sqrt{6x})}{2(8-3x)} = \frac{2(4+\sqrt{6x})}{8-3x} = \frac{8+2\sqrt{6x}}{8-3x}
\]