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Mathematics 22 Online
OpenStudy (anonymous):

Please help me on this one , seriously need help ,getting an incorrect answer \[\Large \frac{ (x-4)^{2005}(x+8)^{2008}(x+1) }{ x ^{2006}(x-2)^{3}(x+3)^{5}(x-6)(x+9)^{2010} } \le 0 \] HELLP

OpenStudy (anonymous):

Let's break this shi*t into bits

OpenStudy (anonymous):

So we will first find the critical points right

OpenStudy (kainui):

Hmm wait what exactly are we trying to find, all possible values of x?

OpenStudy (anonymous):

Critical points:- Nuymerator: 4 , -8 , -1 Denominator: 0, 2 ,-3 , 6 , -9 Yes

OpenStudy (anonymous):

Cool enough?

OpenStudy (anonymous):

@Kainui

OpenStudy (anonymous):

are you there @Kainui

OpenStudy (anonymous):

The thing on the left is some function's derivative?

OpenStudy (kainui):

Ok I see what you're doing. I'm just really tired and sort of out of it, not really on OS it's just open I'm afraid to say.

OpenStudy (anonymous):

we have to use wavy-curve method

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

@ganeshie8 @SithsAndGiggles

OpenStudy (anonymous):

So you're just solving the inequality? The comment about critical points is kind of misleading

OpenStudy (anonymous):

Find the domain of x , in math terms

OpenStudy (anonymous):

what values x can take to satisfy the given inequality

OpenStudy (anonymous):

Right... so the solution set to the inequality.

ganeshie8 (ganeshie8):

you may ignore the even exponents as they are not useful for signs

OpenStudy (dumbcow):

cant you just plug in points on either side of critical points (-8,-1,4) and see where function is less than 0

OpenStudy (anonymous):

My main problem is would the expression be Positive or negative , by plugging 6 that is creating a big nuisancece

OpenStudy (anonymous):

nuisance*

OpenStudy (dumbcow):

just try x=5 instead, x=6 is asymptote which goes to +- infinity

OpenStudy (anonymous):

How do i represent it on a number line

OpenStudy (dumbcow):

|dw:1408164044148:dw|

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