What is the magnitude of the position vector whose terminal point is (-5, 3)?

2 sqrt 17

4

5

6

Question

What is the magnitude of the position vector whose terminal point is (-5, 3)?



2 sqrt 17

4

5

6

sidsiddhartha · Answer

magnitude of a vector is the modulus value like
for a vector--(a,b) 
its magnitude will be
$$mag(a,b)=\sqrt{a^2+b^2}$$

sidsiddhartha · Answer

can u do it now?

ttop0816 · Answer

is it 6?

sidsiddhartha · Answer

nope (-5,3) can be represented as$$V=-5 \hat i+3 \hat j$$
so its magnitude will be
$$|v|=\sqrt{(-5)^2+3^2}=\sqrt{25+9}=\sqrt{34}$$

sidsiddhartha · Answer

got that?

phi · Answer

Based on the answer choices, this question has a typo.

If they said the vector had components (-4,3)  it would work out.
or if then included sqr(34) as a choice...

but as it stands, you should mention to your teacher there is a problem with this question.

ttop0816 · Answer

yes!

ttop0816 · Answer

then it would be 5 because
square root 34= 5.830?

sidsiddhartha · Answer

5.830 is closer to 6 so it should be 6 if sqrt{34} is'nt any option