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Mathematics 16 Online
OpenStudy (anonymous):

simplify

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

I have no idea- I'm sorry

OpenStudy (kirbykirby):

Is this something you are supposed to simplify? Because solving implies there should be an equals sign.

OpenStudy (anonymous):

I dont know that all they put. So I guess simplify..

OpenStudy (kirbykirby):

What a poorly worded question from your instructor :( Some help : \( \cos \theta + \cos \theta = 2 \cos \theta \) So: \((2 \cos \theta )^2 = 2^2 \cos^2 \theta=4 \cos^2 \theta\)

OpenStudy (kirbykirby):

oh ok it is a simplification.. :) Well you have the same thing on both sides of the " + " so you need to add those terms together

OpenStudy (anonymous):

Do I add cos Θ to both sides or.. I'm so confused, sorry.

OpenStudy (kirbykirby):

\((\cos \theta + \cos \theta)^2 \\ = (2 \cos \theta)^2 \\ = 4 \cos ^2\theta \)

OpenStudy (anonymous):

Is there another step after that? xD

OpenStudy (anonymous):

Thats not an answer choice. ;,/

OpenStudy (kirbykirby):

you have that expression twice... you have to add them up

OpenStudy (anonymous):

Do it's D right?

OpenStudy (kirbykirby):

(cos Θ + cos Θ)^2 + (cos Θ + cos Θ)^2 you have "(cos Θ + cos Θ)^2" and you have it again..

OpenStudy (kirbykirby):

\(4 \cos^2 \theta + 4 \cos^2 \theta = ?\)

OpenStudy (kirbykirby):

you can just think of \(\cos ^2 \theta \) like "\(x\)"

OpenStudy (kirbykirby):

yes

OpenStudy (anonymous):

yay, ok. thank you can you help me with another?

OpenStudy (kirbykirby):

ok

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