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Mathematics 21 Online
OpenStudy (anonymous):

general question!

OpenStudy (anonymous):

can i know what does \[b ^{2}-4ac\] actually mean ? how does it affect the the position of the graph ? (as i have memorise the position by positive or negative

OpenStudy (haseeb96):

yes it can be effect the graph by negative numbers

OpenStudy (anonymous):

i know its called discriminent if im not wrong..

OpenStudy (amistre64):

it determines the kind of roots a quadratic has

OpenStudy (the_fizicx99):

It's the discriminate of quadratics, it tells you how many solutions your function is going to have. Whether it touches the x-axis or not. If it doesn't, then you'll have no solutions.

OpenStudy (amistre64):

if D=0, it has one root if D <0 it has complex root and doesnt have any x intercepts if D > 0 it has to distinct real roots

OpenStudy (anonymous):

so it will only have solutions if it touches the x-axis ?

OpenStudy (amistre64):

'real' solutions

OpenStudy (amistre64):

x^2 + 4 = 0 has a solution, but not any 'real' solution

OpenStudy (the_fizicx99):

Yes, "real" solutions, if it doesn't you'll have complex, or imaginary

OpenStudy (the_fizicx99):

Btw it's \(\ \sf \sqrt{b^2 -4ac} \) ^_^

OpenStudy (anonymous):

no.. it just show \[b ^{2}-4ac\] there is no square root

OpenStudy (anonymous):

so its like \[b ^{2}-4ac <0, b ^{2}-4ac = 0, b ^{2}-4ac >0\]

OpenStudy (haseeb96):

b^2-4ac=0 then the roots are real and equal b^2-4ac greater than 0 then roots are real and not equal b^2-4ac less than 0 then roots are complex and real b^2-4ac is the perfect square then roots are rational and not equal

OpenStudy (anonymous):

erm.. where do you determine the roots from ?

OpenStudy (haseeb96):

have u got it @HatcrewS ? http://staff.argyll.epsb.ca/jreed/math20p/quadraticFunctions/quadraticFormula.htm

OpenStudy (haseeb96):

it is written in my math book

OpenStudy (anonymous):

ok i got it! thanks you very much! :D

OpenStudy (haseeb96):

not say thank u just help three persons anywhere and say to them that help more three persons any where .okay :)

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