Its asking a lot but... can someone guide me through a few of these questions and show me what to do?
that's better
Thanks c:
^ ty organic Latte
a polynomial of degree 3 can have at most 3 zeros it must have one zero it cannot have more than 3 because if you have say zeros at \(r_1,r_2,r_3\) then the polynomial will factor as \[p(x)=a(x-r_1)(x-r_2)(x-r_3)\]
Is there a way for them both to be correct? Explain your answer. No a zero of a polynomial is a synonym for where it crosses the \(x\) axis if \(r\) is a zero then \(p(r)=0\) and so \((r,0)\) is on the graph
So since it has a degree of 3 it crosses the x axis 3 times?
i can cross once only like for example \(y=x^3\) only crosses once at \((0,0)\) http://www.wolframalpha.com/input/?i=y%3Dx^3
Ohhh i see
i can have two zeros, touch once and cross once http://www.wolframalpha.com/input/?i=y%3Dx^2%28x-2%29
or it can cross three times http://www.wolframalpha.com/input/?i=y%3D%28x-2%29%28x%2B1%29%28x-4%29
Thank You c:
yw
for part two i would pick \[g(x) = x^3 – x^2 – 4x + 4\] because it is easiest
Then i graph and show the zeros right?
a rational zero of this polynomial has to divide 4 it is pretty obvious that \(g(1)=1-1-4+4=0\)
yeah you can graph it and also factor it here is the graph http://www.wolframalpha.com/input/?i=y%3D+x^3+%E2%80%93+x^2+%E2%80%93+4x+%2B+4
So it has 3 zeros?
you can see that the graph crosses the x axis at \(-2,1,2\) yes three zeros
since those are the zeros that means \[g(-2)=0\\ g(1)=0\\ g(2)=0\] and it also means that it factors as \[g(x)=(x+2)(x-1)(x-2)\]
And the y intercept is 5 right?
the \(y\) intercept is at \(g(0)=4\) the constant, so no not \(5\)\ \((0,4)\) is on the graph
Oh ok... So The Y intercept is 4 because that is where it intercepts the y axis, There are 3 zeros which are \[-2,1,2 \] But I don't get what it means by if it opens upwards or downwards :/
i am not sure what that means either because it is not a quadratic
Maybe because it shows up in the graph from the bottom?
i would say it does neither and this is a mistake in the question you can see the graph from the wolfram link i sent
i would say it does not open up or down, but goes from \(-\infty\) to \(+\infty\) that is more accurate
Oh Ok Thanks c:
yw
you good with this one 4) Esmeralda is graphing a polynomial function as a parabola. Before she begins graphing it, explain how to find the vertex. Make sure you include how to determine if it will be a maximum or minimum point. Use an example quadratic function to help you explain and provide its graph.?
Um... im not really sure... does it come with any equation?
Oh you make an example?
How do you find the x value of the vertex? the \(x\) values of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\)
you want to make up an example? if so make it easy like \(y=x^2+4x-2\) in which case the \(x\) coordinate of the vertex would be \[-\frac{4}{2\times 1}=-2\]
Oh ok... do you simplify it?
How do you find the y value of the vertex? That is easy enough, plug in the \(x\) values to find the \(y\) value in our example since the \(x\) coordinate of the vertex is \(-2\) the \(y\) coordinate is \[y=(-2)^2+4\times (-2)-2=4-8-2=-6\]
lol you do not "simplify" it, you compute it
well the bottom lol 2 times 1
i picked an easy example so that it would be an integer, not a fraction
Oh ok lol now i see XD silly me... but again it shows if it opens upwards or downwards...
now this time that makes sense a parabola opens up or down lets graph the example i wrote http://www.wolframalpha.com/input/?i=y%3Dx^2%2B4x-2
it is real real easy to tell if it opens up or opens down \[y=ax^2+bx+c\] opens up if \(a>0\) and opens down if \(a<0\) i.e. it opens up if the leading coefficient is positive and opens down if the leading coefficient is negative
Ohhh ok
How can he tell if the function has an even or odd degree? if it goes from \(-\infty\) to \(+\infty\) or vice versa, the degree is odd like \(y=x,y=x^3\) etc
it it goes from \(+\infty \) to \(+\infty\) or \(-\infty\) to \(-\infty\) the degree is even like \(y=x^2\)
Does this mean that he can determine the exact number of degrees the function has? hell no you could have a fifth degree polynomial that has 3 zeros just like a 3rd degree polynomial or a fourth degree polynomial that looks like a quadratic
lol Thank You so very much... I really appreeciate it c:
*apreciate
yw hope it is more or less clear sorry about that stupid spam at the beginning i suspended them
Lol Thanks... It was weird :s lol its really rude when people do that though...
lol
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