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rationalizing denominators help ! 4 medals !
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\[\sqrt{8x}\] what could you multiply this by to get 8x?
\(\bf -\cfrac{10}{\sqrt{8x}}\cdot \cfrac{\sqrt{8x}}{\sqrt{8x}}\implies -\cfrac{10{\sqrt{8x}}}{({\sqrt{8x}})^2}\implies ?\)
that seems alot more complicated..
well... the idea being, "simplify" meaning, get rid of the pesky radical in the denominator and the way you'd do it is by multiplying top and bottom by the denominator.... so the denominator ends up squared and thus comes out of the radical
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which still confuses me..
well \(\bf -\cfrac{10}{\sqrt{8x}}\cdot \cfrac{\sqrt{8x}}{\sqrt{8x}}\implies -\cfrac{10{\sqrt{8x}}}{({\sqrt{8x}})^2}\implies -\cfrac{\cancel{ 10 }{\sqrt{8x}}}{\cancel{ 8 }x}\implies ?\)
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