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Mathematics 15 Online
OpenStudy (anonymous):

help

OpenStudy (tylerd):

whats the radius of each gear.

OpenStudy (tylerd):

ok i c sec

OpenStudy (tylerd):

well im thinking we could start by finding the circumference of the smaller one

OpenStudy (tylerd):

and then find the angle of the arc length = to that, on the bigger one

OpenStudy (tylerd):

2piR

OpenStudy (tylerd):

so im getting 18.85 or so

OpenStudy (tylerd):

the circumference of the bigger one is 43.98

OpenStudy (anonymous):

thats what I got.

OpenStudy (tylerd):

so how 18.85 is what percentage of 43.98?

OpenStudy (anonymous):

huh? i don't understand. sorry im terible at math... :'c

OpenStudy (tylerd):

about 42.86 percent or 0.4286

OpenStudy (tylerd):

if you divide the smaller circumference by the larger one

OpenStudy (anonymous):

So now that we have that we can find the arc length?

OpenStudy (tylerd):

we can take a shortcut i think. if a rotation of 43.98 is 360 degrees on the bigger one and were only going rotating around 18.85 18.85/43.98 = 0.4286 we rotated around 42.86 percent of 360 degrees.

OpenStudy (anonymous):

So thats what part 1 is? :D

OpenStudy (tylerd):

yes, thats the shortcut way of doing it i think. to factor in the arc length and all that, id have to think about it a bit more. but its probably basically the same thing

OpenStudy (tylerd):

well the arc length is = the circumference of the smaller one

OpenStudy (tylerd):

yes thats the arc length on the bigger one.

OpenStudy (tylerd):

the angle formed by that arc is what ure trying to find for part 1

OpenStudy (anonymous):

hmmm. How would I do that. I'm confused. Would I multiply or divide that by 360?

OpenStudy (tylerd):

so arc length = theta times radius

OpenStudy (anonymous):

whats the theta?

OpenStudy (tylerd):

the angle

OpenStudy (tylerd):

\[18.85=\theta \times \frac{ \pi }{ 180 } \times 7\]

OpenStudy (tylerd):

thats the formula to find it in degrees

OpenStudy (tylerd):

arclength = theta times pi/180 times radius

OpenStudy (tylerd):

so were trying to solve for theta (this is stil part 1, minus well do it the right way)

OpenStudy (tylerd):

\[18.85= \theta \times \frac{ 7\pi }{ 180 }\]

OpenStudy (tylerd):

we wanna solve for theta

OpenStudy (tylerd):

ya sounds about right

OpenStudy (tylerd):

yep

OpenStudy (tylerd):

i dunno how strict your teacher is on rounding

OpenStudy (tylerd):

but this is close enough for me

OpenStudy (anonymous):

So would that be the answer for Part 1?

OpenStudy (tylerd):

yes

OpenStudy (tylerd):

for part 2 we can do something quite similar

OpenStudy (tylerd):

the circumference of the larger one is 43.98

OpenStudy (tylerd):

so \[43.98 = \theta \times \frac{ \pi }{ 180 } \times 3\]

OpenStudy (tylerd):

im getting something like 839.956 degrees ya

OpenStudy (tylerd):

one rotation is 360 degrees

OpenStudy (tylerd):

so divide by 360

OpenStudy (tylerd):

yep so it rotates approx 2 and 1/3 times

OpenStudy (tylerd):

but it will only make 2 full rotations

OpenStudy (anonymous):

Wow, thank you so much!!! That was a lot of steps lol. Would you mind helping me with one more problem?

OpenStudy (tylerd):

ya i explained it lazily so it seemed like more but

OpenStudy (tylerd):

thats the formula

OpenStudy (anonymous):

Do you want me to close this question and open a new one? Or want to just put it here? :D

OpenStudy (tylerd):

close

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