Question

Solve x^2+10x+14=0 by completing the square?

Answer 1

It cannot be done by factoring

Answer 2

subtract \(14\) and get
\[x^2+10x=-14\]

Answer 3

OK

Answer 4

and then divide the coefficient 10 by 2?

Answer 5

half of 10 is 5, 5 squared is 25, next line should be
\[(x+5)^2=-14+25\] and to from there

Answer 6

yes, what you said

Answer 7

x+5 = sqrt(11)

Answer 8

don't forget the \(\pm\)

Answer 9

right what is the alt code for that?

Answer 10

\pm

Answer 11

\pm

Answer 12

/pm

Answer 13

\( first

Answer 14

and end with \)

Answer 15

anyways is x = -sqrt(11)-5 x = sqrt(11)-5

Answer 16

if you want to see any latex code, right click "show math as" then "latex"

Answer 17

oh /pm\

Answer 18

\pm/

Answer 19

\(\pm\)

Answer 20

right click and you will see it

Answer 21

right click on what?

Answer 22

the code

Answer 23

\(\LaTeX\) right click on the \(\huge \LaTeX\)

Answer 24

show math as tex commands?

Answer 25

ok \[x+5=±\sqrt{11}\]

Answer 26

\[x=-\sqrt{11}-5 , x=\sqrt{11}-5\]

Answer 27

@satellite73

Answer 28

yes

Answer 29

traditionally written as
\[-5\pm\sqrt{11}\] but it is the same

Answer 30

OK, thanks :)