What are the real or imaginary solutions of 125x^3+343=0?
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OpenStudy (anonymous):
\[125x ^{3}+343=0\]
OpenStudy (dangerousjesse):
Real solution:
OpenStudy (dangerousjesse):
Solve for x over the real numbers:\[125 x^3+343 = 0 \]Isolate terms with x to the left hand side.
Subtract 343 from both sides:\[125 x^3 = -343 \]Divide both sides by a constant to simplify the equation.
Divide both sides by 125:\[x^3 = \frac{-343}{125 }\]Elminate the power on the left hand side.
Take cube roots of both sides:
What's your answer?
OpenStudy (anonymous):
\[x=\sqrt[3]{-343/125}\]
OpenStudy (anonymous):
That's probably wrong
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OpenStudy (dangerousjesse):
Can you simplify that any more?
OpenStudy (anonymous):
\[x=\sqrt[3]{2.744}\]
OpenStudy (anonymous):
I'm not the best with simplifying radicals
OpenStudy (dangerousjesse):
Not quite, how about you just simplify the fraction?
OpenStudy (anonymous):
Sorry, I still don't see, -2 93/125?
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OpenStudy (dangerousjesse):
Actually, the answer would just be \[-\frac{7}{5}\]
OpenStudy (anonymous):
Oh
OpenStudy (dangerousjesse):
You were supposed to completely ignore x^3 and find the cube roots of the numerator and denominator.
OpenStudy (anonymous):
7^3/5^3
OpenStudy (anonymous):
yeah I get it now the cuberoot goes to simplify the fration by getting the cubroot of the numerator and denominator.
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OpenStudy (anonymous):
*fraction
OpenStudy (dangerousjesse):
Yep, you can just toss out the powers once you get to that point. Nice job.