What are the real or imaginary solutions of 125x^3+343=0?
\[125x ^{3}+343=0\]
Real solution:
Solve for x over the real numbers:\[125 x^3+343 = 0 \]Isolate terms with x to the left hand side. Subtract 343 from both sides:\[125 x^3 = -343 \]Divide both sides by a constant to simplify the equation. Divide both sides by 125:\[x^3 = \frac{-343}{125 }\]Elminate the power on the left hand side. Take cube roots of both sides: What's your answer?
\[x=\sqrt[3]{-343/125}\]
That's probably wrong
Can you simplify that any more?
\[x=\sqrt[3]{2.744}\]
I'm not the best with simplifying radicals
Not quite, how about you just simplify the fraction?
Sorry, I still don't see, -2 93/125?
Actually, the answer would just be \[-\frac{7}{5}\]
Oh
You were supposed to completely ignore x^3 and find the cube roots of the numerator and denominator.
7^3/5^3
yeah I get it now the cuberoot goes to simplify the fration by getting the cubroot of the numerator and denominator.
*fraction
Yep, you can just toss out the powers once you get to that point. Nice job.
OK, thanks once again :D
Haha no problem :)
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