A circle has its center at (-2, -3) and a radius of 3 units. What is the equation of the circle?
(x + 2)2 + (y - 3)2 = 9
(x - 2)2 + (y - 3)2 = 3
(x + 2)2 + (y + 3)2 = 9
(x + 2)2 + (y + 3)2 = 3
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OpenStudy (anonymous):
@robtobey please help
OpenStudy (acxbox22):
what do you think is the answer?
OpenStudy (cwrw238):
the general form of the equation is
(x - a)^2 + (y - b)^2 = r^2
where center = (a,b) and radius = r
OpenStudy (anonymous):
I dont understand this
OpenStudy (anonymous):
its either a or c
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OpenStudy (cwrw238):
so if you compare this with the above options you'll find the correct one
OpenStudy (anonymous):
is it c?
OpenStudy (cwrw238):
well substitute a = -2 and b = -3 and r = 3 into the general form and you'll get the correct option
OpenStudy (cwrw238):
lets try the first part (x - a)^2
a = -2 , so we have
(x -(-2))^2 = (x + 2)^2
now do the same for b and r
OpenStudy (cwrw238):
do you see what i am doing?
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