Question

Write 2^5=32 in logarithmic form.

Answer 1

Can someone please explain, I forget how to do this.

Answer 2

\[x^{a} = b \rightarrow \log_{x} b = a\]

Answer 3

Plus i t is better to use what @iPwnBunnies said.. :)

Answer 4

so \[\log_{2}32=2 \] then?

Answer 5

no

Answer 6

\[\log_{2}32=5 \]

Answer 7

Hell yeah. B)

Answer 8

Thanks :D

Answer 9

The logarithm operator is used to find exponents. So, you can rewrite stuff with exponents like that.

Answer 10

so you could use log to solve \[\log_{2}x=5 \]

Answer 11

Yes..

Answer 12

K, got it.

Answer 13

Well, it's used to solve what's on the right of the equal sign, which is supposed to be the exponent.
\[2^{x} = 32\]
Solve for x.

\[\log_{2} 32 = x\]

Answer 14

I see