Question

Solve for y: 2y-y^2=(x+c)^2.

Answer 1

Hint: complete the square on LHS

Answer 2

I'm not too good at completing the square. So I got -y^2+2y=-(y^2-2y), now what?

Answer 3

ok
- (y^2 - 2y) = (x + c)^2
y^2 - 2y = -(x = c)^2

(y -1 )^2 - 1 = -(x + c)^2

(y - 1)^2 = 1 - (x + c)^2

can you continue from here?

Answer 4

Let me work it out.

Answer 5

Thanks!

Answer 6

yw

Answer 7

So y-1=sqrt(1-(x+c)^2), right?

Answer 8

right - 0h 2 solutions - positive and negative

Answer 9

+/- what you've written

Answer 10

:)

Answer 11

so add 1 to both sides to get y and you're done

Answer 12

Wait, so if I add 1 to the right side, I got y=1+/-sqrt(1-(x+c)^2), right?

Answer 13

@cwrw238