Question

Radical involving variables must be simplified. Please help!

Answer 1

\[\sqrt[n]{3*2^n*x^(2n)*y^(n+3)}\]

Answer 2

It's x^(2n)*y^(n+3)

Answer 3

a bit confusing, but \(\sqrt[n]{2^n}=2\) for sure

Answer 4

also
\[\sqrt[n]{x^{2n}}=x^2\]

Answer 5

\[\sqrt[n]{y^{n+3}}=\sqrt[n]{y^ny^3}=y\sqrt[n]{y^3}\]

Answer 6

yes and i think i would leave the 3 inside the radical

Answer 7

\[2x^2y \sqrt[n]{3y^ 3}\]

Answer 8

Does that look right? @satellite73

Answer 9

yes