Question

I need some help with deriving trig idententiess.

Answer 1

I need to derive \[1+\tan^2x = \sec^2x \] from \[\sin^2x+\cos^2x=1\]

Answer 2

Divide by cos squared

Answer 3

divide both sides by \(\cos^2(x)\) and you will get it in one step

Answer 4

I got as far as this:

\[\cos^2x = 1 - \sin^2x\]

\[1 = \cos^2x - \tan^2x\]

\[1 + \tan^2x = \cos^2x \]

then im stuck

Answer 5

oh

Answer 6

I see I see let me try it

Answer 7

too much work
don't rearrange the sides, just divide as you see it

Answer 8

I got it thanks :)

Answer 9

yw