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Mathematics 18 Online
OpenStudy (joftheworld):

I NEED HELP WITH COMPOSITE FUNCTION PROBLEMS !!!! PLEASE HELP ME!!

OpenStudy (joftheworld):

OpenStudy (anonymous):

first find \(f(0)\) then find \(g\) of the result

OpenStudy (anonymous):

@Orion1213 & @TylerD would u help himout pls

OpenStudy (joftheworld):

how do i do that ??

OpenStudy (anonymous):

how do you find \(f(0)\) ?

OpenStudy (anonymous):

\[f(x)=-5x+1\\ f(\clubsuit)=-5\clubsuit +1\\ f(0)=-5\times 0+1\]

OpenStudy (joftheworld):

so 1 ?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

your last job is to find \(g(1)\) and you are done

OpenStudy (joftheworld):

is it the same process ?

OpenStudy (anonymous):

u make it sound so simple @satellite73 lol

OpenStudy (joftheworld):

@satellite73 please reply asap..

OpenStudy (anonymous):

yes it is the same process

OpenStudy (joftheworld):

so wouldnt it just be 1 aswell ?

OpenStudy (anonymous):

\[g(x)=x^3\\ g(\diamondsuit)=\diamondsuit^3\\ g(1)=?\]

OpenStudy (anonymous):

yes

OpenStudy (joftheworld):

so the answer is 1 ?

OpenStudy (joftheworld):

what about this one..

OpenStudy (anonymous):

what about it?

OpenStudy (anonymous):

zactly the same but with different functions first find \(f(1)\) then find \(g\) of the result

OpenStudy (joftheworld):

how would this work ? since theres a 1 instead of a 0

OpenStudy (anonymous):

where you see an \(x\) in \(f(x)\) put a \(1\) there

OpenStudy (joftheworld):

so 4 ?

OpenStudy (anonymous):

\[f(1)=4\] your final job is to find \(g(4)\)

OpenStudy (joftheworld):

25 ?

OpenStudy (anonymous):

no \(4^2\neq 25\)

OpenStudy (joftheworld):

16?

OpenStudy (anonymous):

yes

OpenStudy (joftheworld):

so 4 and 16 ? what next?

OpenStudy (anonymous):

you are done, the answer is \(16\)

OpenStudy (anonymous):

\[g(f(1))=g(4)=16\]

OpenStudy (joftheworld):

this one seems more difficult...

OpenStudy (joftheworld):

@satellite73

OpenStudy (anonymous):

not at all what is \(g(30)\) ?

OpenStudy (joftheworld):

i dont know .. can you explain alittle ?

OpenStudy (joftheworld):

@satellite73

OpenStudy (joftheworld):

@midhun.madhu1987

OpenStudy (anonymous):

\[g(x)=\sqrt{x+5}\]\[g(\heartsuit)=\sqrt{\heartsuit-5}\]\[g(5)=?\]

OpenStudy (joftheworld):

5?

OpenStudy (anonymous):

yes

OpenStudy (joftheworld):

so do i multiply by 6 ?

OpenStudy (anonymous):

\[f(x)=2x-8\\ f(5)=?\]

OpenStudy (joftheworld):

hm...

OpenStudy (joftheworld):

i dont get it ..

OpenStudy (anonymous):

where you see an \(x\) replace it by a \(5\)

OpenStudy (joftheworld):

so 2 ?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

it is unfortunate that you are being asked to evaluate a composite function before you really get how to evaluate a function at all but the way to do it is to replace the variable by whatever is in the parentheses

OpenStudy (joftheworld):

so will it be the same thing with this one ?

OpenStudy (anonymous):

pretty much identical try it and see what you get i can check if you like

OpenStudy (joftheworld):

18?

OpenStudy (anonymous):

hmmm no \(g(24)=?\)

OpenStudy (anonymous):

first off i hope it is clear that \[f\circ g(24)\] means first compute \(g(24)\) then compute \(f\) of the result so lets take it step by step what is \(g(24)\) ?

OpenStudy (joftheworld):

\[g(x)=\sqrt{x+1}\]

OpenStudy (joftheworld):

g(1) ?

OpenStudy (anonymous):

not \(g(1)\) they asked for \(g(24)\)

OpenStudy (anonymous):

where you see an \(x\) replace it by \(24\)

OpenStudy (joftheworld):

-207 ?

OpenStudy (anonymous):

\[g(x)=\sqrt{x+1}\\ g(24)=\sqrt{24+1}=\sqrt{25}=?\]

OpenStudy (joftheworld):

i got it now :D thanks !

OpenStudy (anonymous):

whew did you get \(g(24)=5\) and \(f(5)=-9\times 5+9=-36\)

OpenStudy (joftheworld):

yes :D

OpenStudy (joftheworld):

thanks for the help !

OpenStudy (anonymous):

yw

OpenStudy (aum):

\(\large f\circ g(24) = f( g(24) ) \)

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