Question

Can someone help me please? In a triangle EFG, EF=10, FG=8 and EG=14. Find the area of triangle EFG?

Answer 1

Since it is not a right angled triangle, I suggest that you use the Heron's Formula

Answer 2

\[A=\sqrt{s(s-a)(s-b)(s-c)}\]where \(s=\dfrac{a+b+c}2\)

Answer 3

do u mind substitueting the letters with the numbers in the example? so that i understand where they go etc.

Answer 4

a,b,c are the lengths of the sides

Answer 5

\[s=\frac{8+10+14}2=16\]

Answer 6

\[\mbox{Area}=\sqrt{16(16-8)(16-10)(16-14)}\\=\sqrt{16\times8\times6\times2}=\sqrt{16^2\times6}=16\sqrt6\]

Answer 7

ok thats cool thxxx

Answer 8

So you understand the Heron's Formula now?