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OpenStudy (anonymous):
Help plzzz:
In a triangle PQR, 2 of the sides are 5 units long and the included angle is 100°. How long is the third side?
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OpenStudy (anonymous):
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OpenStudy (anonymous):
you know cosine formula??
OpenStudy (anonymous):
yea i do but i dont understand it very well
OpenStudy (anonymous):
see it's like,
\[a^ 2 = b ^2 + c ^2 − 2bc \cos A\]
where both sides b and c has been given and angle A is also given, just need to substitute in it
OpenStudy (anonymous):
okayy ill try it out
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OpenStudy (anonymous):
yeah!! go on )
OpenStudy (anonymous):
So is this right?\[5^2 = 5^2 + c^2 - 2 * 5c * Cos(100)\]
OpenStudy (anonymous):
when substituted?
OpenStudy (anonymous):
oh!!! no actually from my equation you need to calculate "a"...your b and c are the terms are given )
OpenStudy (anonymous):
oh yea course so \[a^2 = 5^2+5^2-2*5*5*\cos(100)\]
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OpenStudy (anonymous):
yeah that one @FishFingersandCustard Now calculate a from that equation )
OpenStudy (anonymous):
thanks so much @aryandecoolest helped so much :D
OpenStudy (anonymous):
no problem ) pleasure to help :D @FishFingersandCustard
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