Question

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The mean weight of the adult population of a country is 67.4 kg, with a standard deviation of 8 kg. If a person is chosen at random, find the probability that that person weighs more than 85 kg.

Answer 1

So let \(X\) be a person's weight. The problem asks you to find \(P(X>85)\).Assuming X is normally distributed, you can standardize X:
\[Z=\frac{X-\mu}{\sigma} \] where \(\mu\) is the mean and \(\sigma\) is the standard deviation.

\[P(X > 85) = P\left( \frac{X-67.4}{8}>\frac{85-67.4}{8}\right)=P(Z>2.2)\]

Answer 2

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Answer 3

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