Question

Lim x->0 sin^2/x

Answer 1

It's supposed to look like \[\lim_{x \rightarrow 0} \frac{ \sin^2x }{ x }\]

Answer 2

Multiply by \(\dfrac{x}{x}\), then use the limit
\[\lim_{x\to0}\frac{\sin ax}{ax}=1\]
for \(a\not=0\).

Answer 3

Thanks!

Answer 4

?

Answer 5

I think you use L'Hopital's Rule giving you \[\lim_{x \rightarrow 0}(\frac{ 2\sin x \cos x }{ 1 })\]

then evaluate limits from there. :)