Assuming x ≠ 0 and y ≠ 0, what is the quotient of

Question

ashy98 · Answer

$$8x ^{9}y ^{3}+2x ^{6}y ^{2}x8x ^{3}y $$
                     $$2x ^{3}y$$

e.mccormick · Answer

Do you mean $\dfrac{8x ^{9}y ^{3}+2x ^{6}y ^{2}x8x ^{3}y}{2x^3y}$

ashy98 · Answer

yes i did know how to do that lol

e.mccormick · Answer

\dfrac{top}{bottom}

e.mccormick · Answer

Is there supposed to be more + or - there?  Because the $2x ^{6}y ^{2}x8x ^{3}y$ looks odd.

ashy98 · Answer

$$8x ^{9} y ^{3}+2 x ^{6} y ^{2}+8x ^{3} y$$

e.mccormick · Answer

OK.  Well, I eould look at what you can facor and cancel.

e.mccormick · Answer

Here is an example:

$\dfrac{12ab^3+6a^2b^2+2a^3b}{4ab} \implies$

$\dfrac{2(6ab^3+3a^2b^2+a^3b)}{2(2ab)} \implies$

$\dfrac{\cancel{2}(6ab^3+3a^2b^2+a^3b)}{\cancel{2}(2ab)} \implies$

But that is not all that factors and cancels in this case.  I can do an a and a b too.

$\dfrac{ab(6b^2+3ab+a^2)}{2ab} \implies$

$\dfrac{\cancel{ab}(6b^2+3ab+a^2)}{2\cancel{ab}} \implies$

$\dfrac{6b^2+3ab+a^2}{2} $