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Write the quadratic equation whose roots are −4 and −6 , and whose leading coefficient is 4 .
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x = -4 and x = -6 so x + 4 = 0 and x + 6 = 0 (x + 4)(x + 3) = 0 x^2 + 3x + 4x + 12 = 0 x^2 + x + 12 = 0 Multiplying by 4 4x^2 - 4x - 48 = 0
4x^2 + 4x + 48 = 0
well since the zeros are -4 and -6 then you quadratic function is written like this \(\Large \color{midnightblue}{f(x)=a(x+6)(x+4)}\) a is given to you to be 4 so \(\Large \color{midnightblue}{f(x)=4(x+6)(x+4)}\) you question didn't really as if we should write it in standard form so i suppose you just leave that way
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