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Mathematics 20 Online
OpenStudy (anonymous):

Please check my work Algebra

OpenStudy (anonymous):

• 3 √x^3 (a^m)^n = a^mn x^3(1/3) 3(1/3) = 1 x • x^1/3 • x^1/3 • x^1/3 a^m * a^n = a^m+n 1/3 * 1/3 * 1/3 = 3/3 3/3 = 1 x • 1 / x^-1 cancel each other out x^1 x • 11 √x^5 * x^4 * x^2 a^m * a^n = a^m+n 11√x^5+4+2 11√x^11 x^11 * 1/11 x

OpenStudy (anonymous):

Just these 4 questions

OpenStudy (anonymous):

@phi @ganeshie8 @KlOwNlOvE

OpenStudy (anonymous):

\[\sqrt[3]{x^3}=x\] is correct

OpenStudy (anonymous):

\[(x^{\frac{1}{3}})^3=x\] is also correct

OpenStudy (anonymous):

\[\sqrt[11]{x^{11}}=x\] is also correct

OpenStudy (anonymous):

what about the 3rd one? i'm not sure if my work is right with it

OpenStudy (anonymous):

• 1 / x^-1 cancel each other out x^1 x

OpenStudy (anonymous):

yes although i would not use the word "cancel"

OpenStudy (anonymous):

\[\frac{1}{x^{-1}}=x^1=x\] because \(b^{-n}=\frac{1}{b^n}\)

OpenStudy (anonymous):

ok, thanks for all the help and feedback!

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