Question

-7x^2 - 23x + 10 = 0

What are the solutions of the quadratic equation?

Answer 1

try using the quadratic formula

Answer 2

given: ax^2 + bx + c = 0

x = -b +- sqrt(b^2 - 4ac)
-------------------
2a

Answer 3

I think it's the first answer

Answer 4

Solve for x over the real numbers:
\[\large -(7 x^2)-23 x+10 = 0 \]Multiply both sides by a term to make the coefficient of x^2 positive.
Multiply both sides by -1:
\[\large 7 x^2+23 x-10 = 0 \]Using the quadratic formula, solve for x.
\[\large x = \frac{-23±\sqrt{23^2-4×7 (-10)}}{2×7} = \frac{-23±\sqrt{529+280}}{14} = \frac{-23±\sqrt{809}}{14}:\]

Answer 5

\[23\pm \sqrt{809}\]

Answer 6

over -14

Answer 7

I got \(\large \frac{-23+\sqrt{809}}{14}\) or \(\large \frac{-23-\sqrt{809}}{14}\)

Answer 8

hmm okay