Can someone please help! I will fan+medal! 2=log(3x+4) 1.Convert the logarithmic equation to an exponential equation. 2. Simplify and solve the equation to get the solution
there's no explicit log base.. meaning... is "10", so you know \(\bf y=log_{\color{red}{ a}}({\color{blue}{ b}})\implies {\color{red}{ a}}^y={\color{blue}{ b}}\qquad thus \\ \quad \\ 2=log(3x+4)\implies 2=log_{\color{red}{ 10}}({\color{blue}{ 3x+4}})\implies ?\)
\[10^{2}=3x+4\]
so x=32?
yes !
awesome, can you help me out with another problem?
sure !
I will write the equation in a sec. 1. Combine the exponential expressions to produce a single exponential expression. 2.Convert the equation from Part 1 to a logarithmic equation 3. Solve the equation |dw:1408746293813:dw|
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