An insurance company looks at its auto insurance customers and finds that a) All insure at least 1 car b) 85% insure more than 1 car c) 23% insure a sports car d) 17% insure more than 1 car, including a sports car. Find the probability that a customer selected at random insures exactly 1 car and it is not a sports car Please, help me arrange it.
100%? a) All insure at least one car
yup
Alright then. That wasn't so hard. :)
Wonder how it helps!!
..0.o?
it's not 100 though...
it's not 100, it's 100%
no it's not that either
why?
*Exactly 1 car* vs atleast 1 car
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no, a says that every person in your sample group insures 1 car at the minimum
Oh... you have a point there Fionacci.
then 2 says of those 100%, 85% actually have at least 2 cars
So are you thinking 15% then?
no, not even there yet, you have to use proportions and it's not possible to be exact cause they overlap
because 23% of the 100% insure a sports car
but they can be in the 85% as well
at maximum it is 15%
Huh...beats me. Good thing your here. :)
haha I'm just reinterping from the given, not actually doing it atm
the important one is 4 though because that says 17% of the 100% but also intersects with the 85%
you would have to assume every person is only accounted for once, but that isn't accurate since 23%=/15%
At the end up, I got nothing, hihihi ...
|dw:1408755395541:dw| and fill in the blank, I have
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