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Mathematics 18 Online
OpenStudy (loser66):

An insurance company looks at its auto insurance customers and finds that a) All insure at least 1 car b) 85% insure more than 1 car c) 23% insure a sports car d) 17% insure more than 1 car, including a sports car. Find the probability that a customer selected at random insures exactly 1 car and it is not a sports car Please, help me arrange it.

OpenStudy (anonymous):

100%? a) All insure at least one car

OpenStudy (loser66):

yup

OpenStudy (anonymous):

Alright then. That wasn't so hard. :)

OpenStudy (loser66):

Wonder how it helps!!

OpenStudy (fibonaccichick666):

..0.o?

OpenStudy (fibonaccichick666):

it's not 100 though...

OpenStudy (loser66):

it's not 100, it's 100%

OpenStudy (fibonaccichick666):

no it's not that either

OpenStudy (loser66):

why?

OpenStudy (fibonaccichick666):

*Exactly 1 car* vs atleast 1 car

OpenStudy (loser66):

|dw:1408754513736:dw|

OpenStudy (fibonaccichick666):

no, a says that every person in your sample group insures 1 car at the minimum

OpenStudy (anonymous):

Oh... you have a point there Fionacci.

OpenStudy (fibonaccichick666):

then 2 says of those 100%, 85% actually have at least 2 cars

OpenStudy (anonymous):

So are you thinking 15% then?

OpenStudy (fibonaccichick666):

no, not even there yet, you have to use proportions and it's not possible to be exact cause they overlap

OpenStudy (fibonaccichick666):

because 23% of the 100% insure a sports car

OpenStudy (fibonaccichick666):

but they can be in the 85% as well

OpenStudy (fibonaccichick666):

at maximum it is 15%

OpenStudy (anonymous):

Huh...beats me. Good thing your here. :)

OpenStudy (fibonaccichick666):

haha I'm just reinterping from the given, not actually doing it atm

OpenStudy (fibonaccichick666):

the important one is 4 though because that says 17% of the 100% but also intersects with the 85%

OpenStudy (fibonaccichick666):

you would have to assume every person is only accounted for once, but that isn't accurate since 23%=/15%

OpenStudy (loser66):

At the end up, I got nothing, hihihi ...

OpenStudy (loser66):

|dw:1408755395541:dw| and fill in the blank, I have

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