Question

How would you turn this into a logarithmic function? f(x)=2.59e^(.08x)

Answer 1

@UnkleRhaukus

Answer 2

divide both sides by that constant 2.59,

then take the logarithm of both sides (to base e)

Answer 3

can you do the first step?

Answer 4

No I can't I don't know how.

Answer 5

f(x)=2.59e^(.08x)

\(\dfrac{f(x)}{2.59}\) = \(\dfrac{2.59}{2.59}\) e^(.08x)

Answer 6

Which equates to this? f(x)/2.59=e^(.08x)

Answer 7

yeap

Answer 8

so now now take the natural log of both sides,

ln [ f(x)/2.59 ] = \ln [ e^(.08x) ]
=

Answer 9

f(x)=2.59e^(.08x)

y= 2.59e^(.08x)

y/2.59=e^(.08x)

In(y/2.59)=In e^(.08x)

In y – In 2.59= In e^(.08x)

In y = In e^(.08x) + 0.95

In y = (.08x) + 0.95

This Is what I had before. Was it correct? It seemed wrong so I said I had no Idea how to do it.

Answer 10

I replaced f(x) with y. to graph with. (suppose to use w/o technology.)

Answer 11

f(x) =2.59e^(.08x)
you set f(x) = y , this is fine
y = 2.59e^(.08x)
dividing by the constant
y/2.59 =e^(.08x)
taking the natural log
In(y/2.59) =In e^(.08x)
log rules ,
In y – In 2.59 = (.08x)

In y = (.08x) + In 2.59
i'd leave answer as this or maybe
In f(x) = (.08x) + In 2.59

Answer 12

oh, you have to graph it? then i guess approximating the log with a decimal is a good idea too then

Answer 13

you had it right

Answer 14

Oh wow, thank you. I guess I surprised myself.