Question

Please Solve lim x-0 cotx/lnx using L,hopital's rule....
anybody help me ?

Answer 1

so did you take the derivative of numerator and denominator separately ??
what did u get ?

Answer 2

derivative of cot x is ??
derivative of ln x is ?

Answer 3

In L-Hospital Rule we generally take the derivative of numerator and denominator separately.
You might need some references.
\[\Large \frac{d}{dx}(\cot x)=?\]
\[\Large \frac{d}{dx}(\ln x)=?\]

Answer 4

-csc^2x
and 1/x

Answer 5

so you have -x csc^2 x
right ??

how do u convert csc x to sin x ?>

Answer 6

nt rly reqd :o

Answer 7

you will need this :

lim x->0 sin x/x =1

Answer 8

cosec 0 is infinity, right ?
0*infinity is still not defined

Answer 9

\[\Large \frac{-cosec^2 x}{\frac{1}{x}} = \lim_{x \rightarrow 0}- x cosec^2 x\]
anything into 0 is 0

Answer 10

its 0 only...

Answer 11

anything except infinity **

Answer 12

limiting value is 0 only
but there's a mathametical way to prove that, so why not

Answer 13

im out here

Answer 14

thanks DLS and hartnn

Answer 15

you got how to solve ?

Answer 16

and sure, you're welcome ^_^

Answer 17

yes i'll solve it now..

Answer 18

isn't this function divergent?