Question

Fan&Medal

Answer 1

http://prntscr.com/4fsihu

Answer 2

@campbell_st @KlOwNlOvE @nikato @zepdrix

Answer 3

There are two ways to find the axis of symmetry of a parabola. If in vertex form (\[f(x)=(x-h)^2 +k\]) then the axis is x=h. If the equation is in standard form (\[f(x)=ax^2+bx+c\]) then the axis of symmetry is found at \[x=-b/2a\]

Answer 4

so what do i do first

Answer 5

Alright, well in the screenshot the first equation, f(x), is in vertex form so the axis of symmetry is x=h. The second equation, g(x) is in standard form. Plug in the information corresponding to the formula to find the axis of symmetry. Once you have them you can then rank them from smallest to largest.

Answer 6

honestly i dont know how to do this lol

Answer 7

@akeith15

Answer 8

Okay, so the first equation is:
\[f(x)=3(x+4)^2 + 1\]
By using the basic formula for a parabola in vertex form, we see that h = 4, and that the axis of symmetry is x = h. Therefore, the axis of symmetry is x = 4 for the first function.

Answer 9

ok

Answer 10

so whats next @akeith15

Answer 11

Alright so now we know that the axis of symmetry for the function f(x) is: x = 4, we can do the same thing for g(x). The only difference being that g(x) is in standard form. we can use the basic formula of a parabola in standard form to find the variables we need: "a" and "b"

For g(x):
a = 2
g = -16

Then we put these into the axis of symmetry formula
\[x=-b/2a\]
\[x=-(-16)/2(2)=4\]

Therefore the axis of symmetry for g(x) is x = 4.

Edit: above I said the axis of symmetry for f(x) was 4, it's -4. That was a typo on my part, sorry.

Then we can look at the graph of h(x) and see the axis of symmetry is x = 1.

So ranking from smallest to largest we get: f(x), h(x), g(x)

I hope that helps.

Answer 12

thx