Question

Find all the zeros of each polynomial function.

f(x) = x4 + 4x3 – 6x2 – 36x – 27


Select one:


a. ±1 and ±3

b. ±3 only

c. ±1 only

d. none of the above

Answer 1

@TylerD

Answer 2

try the factors of the coefficient + and - and substitute them into the eqn. those with an answer of 0 are the zeros

1.f(x)=x^4+4x^3-6x^2-36x-27
f(1)=1^4+4(1)^3-6(1)^2-36(1)-27 = -64 not a zero
f(-1)= (-1)^4+4(-1)^3-6(-1)^2-36(-1)-27 = 0 thus zero

x = -1 is a zero so (x+1) is a factor of the polynomial

if you look at your answers 1 is not a zero s0 ??

Answer 3

but -1 is

Answer 4

so which answer are we looking at

Answer 5

@TylerD

Answer 6

since you are given options, perhaps the easiest thing to do would be to check

Answer 7

\[f(x) = x^4 + 4x^3 – 6x^2 – 36x – 27 \]
\[f(1) = 1 + 4– 6 – 36 – 27 \neq 0\] so that eliminates A and C

Answer 8

ok

Answer 9

is it D non of the above