Question

What is the equation of the ellipse with foci (-10, 0), (10, 0) and co-vertices (0, -3), (0, 3)?


x squared divided by 109 minus y squared divided by 9 equals 1

x squared divided by 109 plus y squared divided by 9 equals 1

x squared divided by 100 minus y squared divided by 9 equals 1

x squared divided by 100 plus y squared divided by 9 equals 1

Answer 1

The given eclipse is horizontal eclipse....
since foci is (+/-ae,0) so .......ae=10
since co-vertices is (0,+/-b), b=3, now
\[,a^2=b^2+(ae)^2\]
after this substitute this values in main equation.....

Answer 2

Hope it's clear!!!!! @chappy0729

Answer 3

thank you @aryandecoolest

Answer 4

np ) anyitme :D @chappy0729