What is the equation of the ellipse with foci (-10, 0), (10, 0) and co-vertices (0, -3), (0, 3)?

x squared divided by 109 minus y squared divided by 9 equals 1

x squared divided by 109 plus y squared divided by 9 equals 1

x squared divided by 100 minus y squared divided by 9 equals 1

x squared divided by 100 plus y squared divided by 9 equals 1

Question

What is the equation of the ellipse with foci (-10, 0), (10, 0) and co-vertices (0, -3), (0, 3)?
 	
	
x squared divided by 109 minus y squared divided by 9 equals 1
	
x squared divided by 109 plus y squared divided by 9 equals 1
	
x squared divided by 100 minus y squared divided by 9 equals 1
	
x squared divided by 100 plus y squared divided by 9 equals 1

anonymous · Answer

The given eclipse is horizontal eclipse....
since foci is (+/-ae,0) so .......ae=10
since co-vertices is (0,+/-b), b=3, now
$$,a^2=b^2+(ae)^2$$
after this substitute this values in main equation.....

anonymous · Answer

Hope it's clear!!!!! @chappy0729

anonymous · Answer

thank you @aryandecoolest

anonymous · Answer

np ) anyitme :D @chappy0729