Mathematics
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OpenStudy (anonymous):
Help me please. fan and medal
Given the parent function f(x) = 2x, show a graph that shows f(x) + 1?
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OpenStudy (anonymous):
@Hero
OpenStudy (anonymous):
that isn't one of my choices )):
OpenStudy (anonymous):
all of my choices are curves
OpenStudy (anonymous):
Are you sure you've copied it exactly? It shouldn't be a curved graph.
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hero (hero):
^What he said
OpenStudy (anonymous):
Given the parent function f(x) = 2x, which graph shows f(x) + 1?
OpenStudy (anonymous):
@Hero
hero (hero):
That's \(f(x) = 2^x\) which is completely different from \(f(x) = 2x\)
hero (hero):
\(f(x) = 2^x\) is an exponential function.
\(f(x) = 2x\) is a linear function.
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OpenStudy (anonymous):
ohhhhhhhhh.........
OpenStudy (anonymous):
what line to I look at?
hero (hero):
Hint: The graphs are color-coded
OpenStudy (anonymous):
A?
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hero (hero):
Correct
OpenStudy (anonymous):
Using the graph below, calculate the average rate of change for f(x) from x = 0 to x = 2.
OpenStudy (anonymous):
x = −4
x = −2
x = 2
x = 4
would it be x=2?
OpenStudy (anonymous):
@Hero
OpenStudy (princeharryyy):
still need help @izthewiz7
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OpenStudy (anonymous):
Yes, on the last thing two comments @princeharryyy
OpenStudy (princeharryyy):
do u kno wat average rate mean @izthewiz7
OpenStudy (anonymous):
the point at which two lines intersect? @princeharryyy
OpenStudy (princeharryyy):
nope @izthewiz7
OpenStudy (princeharryyy):
(y2-y1)/(x2-x1)
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OpenStudy (anonymous):
I don't understand how I can get the answer from that
OpenStudy (princeharryyy):
can u find out what would be the f(x) from the given graph it would be
OpenStudy (princeharryyy):
@izthewiz7
OpenStudy (anonymous):
4? @princeharryyy
OpenStudy (princeharryyy):
see this curve can u guess wat type of function it would b @izthewiz7
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OpenStudy (anonymous):
no. im just really confused.
OpenStudy (princeharryyy):
ohk tell me in wat u are confused ?
OpenStudy (anonymous):
everything.
OpenStudy (princeharryyy):
see this curve is f(x) = 3^x - 3
OpenStudy (princeharryyy):
so y2 occurs at x=2 => y2= 3^2-3 =>y2=6
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OpenStudy (princeharryyy):
similarly y1 occurs at x=0 so, y1= 3^0 -3 =>-2
OpenStudy (princeharryyy):
so from the formula i gave u earlier (y2-y1)/(x2-x1) => (6-(-2))/(2-0) => 4 as your answer @izthewiz7
OpenStudy (princeharryyy):
r u getting anything @izthewiz7
OpenStudy (princeharryyy):
please b quick i don't have ample time @izthewiz7