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Mathematics 15 Online
OpenStudy (anonymous):

I need help with Tangent, Sine, and Cosine ratios!

OpenStudy (anonymous):

OpenStudy (shadowlegendx):

Well, what do you know about Tan, Sin, and Cos?

OpenStudy (anonymous):

They're trig functions :D

OpenStudy (anonymous):

I'm just confused. How can I figure anything out if I don't have the lengths of a, b, or c..

OpenStudy (anonymous):

Sin of B= b/a

OpenStudy (shadowlegendx):

Soh... Sine = Opposite / Hypotenuse ...cah... Cosine = Adjacent / Hypotenuse ...toa Tangent = Opposite / Adjacent

OpenStudy (anonymous):

What is SOHCAHTOA? @loginJ

OpenStudy (shadowlegendx):

@dan815 Be useful and stop creeping da chats!

OpenStudy (anonymous):

S stands for sin: The O and the H with it stand for what it means: Opposite over Hypotenuse

OpenStudy (anonymous):

an annoying mnemonic devise

OpenStudy (anonymous):

C stands for cosine: and the a and the H along with it stand for: Adjacent over hypotenuse

OpenStudy (anonymous):

and T stands for tangent and the A and the O with it stand for: Adjacent over Opposite

OpenStudy (anonymous):

Does that make sense @MaryLovell15

OpenStudy (anonymous):

Yeah, I understand.

OpenStudy (anonymous):

Could someone give me an example of the answer they are looking for. Just so I can see what to do. For tan A.

OpenStudy (the_fizicx99):

Sine = \(\ \dfrac{Oppo.}{Hypo.} \) Using angle B, |dw:1408932650013:dw| Therefore \(\ \sf Sin B = \dfrac{b}{c} \) Got it?

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