May you help me with this problem? @mathstudent55
Notice I states BGCH is a parallelogram. The reason is opp sides are parallel. Nothing has been stated yet about parallel sides, so I cannot be the first of these statements.
Also notice II uses a property of a parallelogram, so it's logical that II must follow I
Meaning, II is also out- correct?
The first of the statements must be IV. From the figure and the construction, you can state IV.
It is between B and D then.
IV, III, I, II
If you want, I'll explain it to you.
Why wouldn't it be "D" , I thought I went last?
No. They used it the other way. The definition of a parallelogram is: A parallelogram is a quadrilateral that has two pairs of parallel opposite sides.
You agree with that definition?
Yes.
A definition can be used two ways in a proof. If one statement of a proof states a quadrilateral is a parallelogram, then using the definition, you can state the opposite sides are parallel. That is one way of using the definition.
The other way of using the definition is: If you state that a quadrilateral has both pairs of opposite sides parallel, you can use the definition to state the quadrilateral is a parallelogram.
In other words a definition works both ways.
This is not the case with a theorem or a postulate.
For theorems and postulates, the converses must be either proved (in the case of a theorem) or a new postulate must be assumed (in the case of a postulate.)
I can go over this step by step to show the logic of the order of the steps.
II is similar to CPCTC. Do you know CPCTC for congruent triangles?
corresponding parts of congruent triangles are congruen , yeah
congruent*
Right. How do you use CPCTC? Let's say you need to prove two segments are congruent. It just so happens that the segments are corresponding parts of two triangles. If you can show the triangles are congruent, then you can state the segments are congruent by CPCTC.
In our case, we want to show that seg. BD is congruent to seg. DC. If we prove quad. BGCH is a parallelogram, then we can use the property of parallelograms that their diagonals bisect each other to state that seg. BD is congruent to seg. DC.
That is why statement II must follow statement I. In statement I we prove BGCH is a parallelogram. In statement II we draw a conclusion from the fact that BGCH is a parallelogram.
We used statements IV and III to prove BGCH is a parallelogram. That means statements IV and III must come before statement I.
Now between statements IV and III, how do you know which one comes first?
Statement IV comes first (before statement III), because from the figure you have, you can conclude the statement of statement IV.
Thank you soo much for condensing this information, sometimes it's so intimidating and you just make it so much more clearer and understandable than what it really is.. :D
!!!!*
You're welcome. Statement IV comes directly from info you already have before these 4 steps you have to put in order.
Ah. I have 3 more that I don't get. May I tag you in them as well?
Sure.
For statement IV, look at triangle ABH. We already know AF = FB We also know AG = GH From that info we use the midsegment theorem to state FG is parallel to BH. We do a similar thing with triangle AHC to get GE parallel to HC. This is all statement IV which comes from statements we already have above. Then by substitution we do statement III. Then we do statements I and II in that order.
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