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Mathematics 21 Online
OpenStudy (anonymous):

For the data in the table, tell whether y varies directly or indirectly with x. Write an equation for the direct or indirect variation .

OpenStudy (anonymous):

OpenStudy (anonymous):

@zepdrix

zepdrix (zepdrix):

Hey broski c: Hmm, so th x values close to 0 produce large y's. The y's get smaller as x increases in either direction. We can describe this as an inverse relationship. \(\Large\rm y=\dfrac{k}{x}\)

zepdrix (zepdrix):

We need to use the information they gave us to find our k value.

zepdrix (zepdrix):

Let's plug in the coordinate point (3,5) and see what our k value is, \(\Large\rm 5=\dfrac{k}{3}\) What do you get for k? c:

OpenStudy (anonymous):

3 ? O: @zependrix

OpenStudy (anonymous):

@zepdrix

zepdrix (zepdrix):

5 equals k divided by 3 5 equals one third of k So we need to multiply the 5 by 3 to find our k. lol zependrix XD

OpenStudy (anonymous):

15? @zepdrix

OpenStudy (anonymous):

And hahah i typed it wrong xD

zepdrix (zepdrix):

Ok great! k=15, Plugging that in gives us, \(\Large\rm y=\dfrac{15}{x}\)

OpenStudy (anonymous):

Ok so the answer is k= 15/x right? But is it vary directly or inderectly? @zepdrix

OpenStudy (anonymous):

Indirectly right? @zepdrix

zepdrix (zepdrix):

you -_- you and your ways.. -_- no not k=15/x, look back at what i just wrote :d direct or indirect? You should be able to find tht info from my first post D:

zepdrix (zepdrix):

Oh I called it an `inverse relationship`, sorry. that's another word for `indirect`.

OpenStudy (anonymous):

See it is indirect -.- lol but 15 right? @zepdrix

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