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Mathematics 14 Online
OpenStudy (anonymous):

I need help ASAP on this question.

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 would you be able to help me on this problem?

OpenStudy (anonymous):

@aaronq , @mathstudent55 , @mathmale , @myko please i need help on this

OpenStudy (anonymous):

@mathmale ?

OpenStudy (anonymous):

This is chapter 14 in trig

OpenStudy (anonymous):

|dw:1409082203083:dw| Length of on side of the regular n-gon l can be calculated by using cosine formula or some other method. Using cosine formula, \(l = sin ^2 \frac{\pi}{n} \) So the perimeter of the n-gon is \( n \times l = n \times \sin ^2 \frac{\pi}{n}\) Now put different values of n. For instance (a) n = 3 \(Perimeter = 3 \times sin ^2 \frac{\pi}{3} = 3 \times 3/4 = 9/4 \) Similarly do for other values of n

OpenStudy (anonymous):

*one

OpenStudy (anonymous):

Sorry! Actually, \( l = 2 \times sin \frac{\pi}{n} \)

OpenStudy (anonymous):

so not sin^2 pi/n right?

OpenStudy (anonymous):

ok got it

OpenStudy (anonymous):

I need help on letter g because it is just a variable and any type of explanation for it would be helpful as well.

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

any help on letter g would be appreciated

OpenStudy (abb0t):

@Squirrels

OpenStudy (amistre64):

part g is a generalization, can you develop a formula, or is there a formula given to find the required solution for any n-sided polygon

OpenStudy (amistre64):

i notice it hints at law of cosines ...

OpenStudy (anonymous):

The equation I used was from @ShailKumar

OpenStudy (amistre64):

c^2 = a^2 + b^2 -2ab cos(C) seeing that this is in a unit circle, the a=b=1 c^2 = 2 -2cos(C) c^2 = 2(1-cos(C)) etc

OpenStudy (amistre64):

if the required angle is in radians, then C = 2pi/n if in degrees then its C = 360/n and since c is equal to 1 side, we need n sides

OpenStudy (anonymous):

the equation I was using to solve for the other numbers was |dw:1409095742760:dw|

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