I need help ASAP on this question.
@ganeshie8 would you be able to help me on this problem?
@aaronq , @mathstudent55 , @mathmale , @myko please i need help on this
@mathmale ?
This is chapter 14 in trig
|dw:1409082203083:dw| Length of on side of the regular n-gon l can be calculated by using cosine formula or some other method. Using cosine formula, \(l = sin ^2 \frac{\pi}{n} \) So the perimeter of the n-gon is \( n \times l = n \times \sin ^2 \frac{\pi}{n}\) Now put different values of n. For instance (a) n = 3 \(Perimeter = 3 \times sin ^2 \frac{\pi}{3} = 3 \times 3/4 = 9/4 \) Similarly do for other values of n
*one
Sorry! Actually, \( l = 2 \times sin \frac{\pi}{n} \)
so not sin^2 pi/n right?
ok got it
I need help on letter g because it is just a variable and any type of explanation for it would be helpful as well.
@amistre64
any help on letter g would be appreciated
@Squirrels
part g is a generalization, can you develop a formula, or is there a formula given to find the required solution for any n-sided polygon
i notice it hints at law of cosines ...
The equation I used was from @ShailKumar
c^2 = a^2 + b^2 -2ab cos(C) seeing that this is in a unit circle, the a=b=1 c^2 = 2 -2cos(C) c^2 = 2(1-cos(C)) etc
if the required angle is in radians, then C = 2pi/n if in degrees then its C = 360/n and since c is equal to 1 side, we need n sides
the equation I was using to solve for the other numbers was |dw:1409095742760:dw|
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