Question

I'm doing an assignment in flvs algebra 2 and I'm completely stuck on the last part of this problem, could someone please help??!!

Now it is your turn to plan the trajectories required to launch a spacecraft through a specific route in space. The launch area is identified on the map below.
http://leon.flvs.net/webdav/educator_algebraII_v13/module01/images/01_05_assessment/01_05_assessment_b.png

Launch Area:___(1, 2)___
Point A:___(0, 3)___
Point B:___(-3, 0)___
Point C:___(-1, -4)___
1. standard form from launch point to point a.
I got x+y=3
2 point-slope form of point a to b

Answer 1

I got y-3=x+3.
3.slope-intercept of b to c.
I got y=-2x-6
4.Convert x+y=3 to slope intercept.
I got y=-x+3
5. Reflect back on this scenario and each equation you created. Would any restrictions apply to the domain and range of those equations? Explain your reasoning using complete sentences. (I'm stuck on this one!!!!)

Answer 2

The link will only work for those who have an account there and are logged in.

Answer 3

@aum how bout now?

Answer 4

@aaronq can you help, I've heard good things about you

Answer 5

An yea, don't give out your user names and passwords to anyone to help them log into your account. I suggest getting the software called LightShot, this way you can use your "PrtScn" button on your keyboard after making a selection, be able to save it as an image, and then link it to show people the problems you have questions on. That's just a suggestion of course, but it really helps me out.

Answer 6

Thanks @Cosmichaotic

Answer 7

1. (1,2) and (0,3)
Slope = (3-2)/(0-1) = -1
y = mx + b = -x + b
y =3 then x = 0
3 = 0 + b. b = 3
y = -x + 3
x + y = 3 (your answer is correct).

2. (0,3) and (-3, 0)
slope = (0-3)/(-3-0) = -3/-3 = 1
Point Slope form:
(y - 3) = 1 * (x - 0)
y - 3 = x

Answer 8

So the point-slope form for #2 is y-3=x?

Answer 9

That is what I am getting. You can double check the calculation.

Answer 10

For 3) I am also getting y = -2x - 6.

Answer 11

Your 4) is also correct.

Answer 12

Sweet! I have no idea how to check number 5 though, could you possibly help me on that?

Answer 13

The rocket can go anywhere to the left or right and so I am guessing x can be any value. So I guess no restriction on the domain. But I am guessing, a negative y-value would mean going below the ground and so the range may be restricted to \(y \ge 0\).

Answer 14

Assuming y = 0 represents the ground level.

Answer 15

Thats the only thing that I can think of too, thanks for the info! I also double-checked number 2 and you were correct, thanks!

Answer 16

You are welcome.