what is the limit of x^8/3 as x approaches 1000 from the right
what does that last part of the statement say?
the natural log of x to the nth power is equal to ?
Why is log needed to evaluate this limit? The function is continuous at x=1000 which means you can just plug the number in to find that limit.
im just so confused all together, ive been working on calculus for like 6 hour..... i just want to finish my homework lol
so I take that back, i think ive been working on this for to long lol all you really needed to do was take 1000 and rase it to (8/3) thank you everyone for putting up with me...
Whether it was x^(8/3) or x^8/3, both of these are continuous over the interval (-inf,inf), so you could use direct substitution here.
In fact, I will state something in general: If f is a function continuous at x=c, then \[\lim_{x \rightarrow c}f(x)=f(c) .\]
sorry i want wrong way this is the solution of it |dw:1409118876698:dw|
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