Question

Show that sin 3 theta = 3 sin theta - 4 sin^3 theta.

Answer 1

Hence, show that sin 3 theta- cos 2 theta = (1-s)(4s^2+2s-1), where s = sin theta

Answer 2

@ikram002p

Answer 3

use identety of sin(A+B)

since 3=2+1

Answer 4

That's all

Answer 5

simplify

Answer 6

lets do it together :)

Answer 7

ok

Answer 8

sin(A+B)
=sin A cos B + cos A sin B
=

Answer 9

I'm nt sure

Answer 10

Hw do I begin

Answer 11

\(\large \sin 3 \theta=\sin (2 \theta +\theta)=\sin 2 \theta \cos \theta +\cos 2\theta\sin \theta \)

Answer 12

ok
what do I need to simplify

Answer 13

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Answer 14

like this ?