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find two-three digit numbers whose sum is multiple of 504 and quotient is multiple of 6..
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please interpret the que also
Say the two numbers are \(A\) and \(B\) such that \(A > B\) : \(\large A + B = 504t\) \(\large \dfrac{A}{B} = 6 \implies A = 6B \) combining above both you get : \(\large 6B + B = 504t \implies B = 72t\)
plugin \(t = 1\), you get \(B = 72*1 = 72\) But you want a 3 digit number, so discard this
pluging \(t = 2\), whatd do you get ?
144
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yes, since it is a 3 digit number you're okay with B how about A ?
use \(\large \dfrac{A}{B}=6\) to find \(A\)
432..?
yes, t > 2 will not work, why ?
hey you get B = 144*6 = 864, right ?
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cuz its 3 digit no
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