Question

Let h=v0^2/4.9 sin(theta)cos(theta) model the horizontal distance in meters traveled by a projectile. If the initial velocity is 36 meters/second, which equation would you use to find the angle needed to travel 100 meters? 7.36sin(2) = 100 132.12sin(2) = 100 264.49sin(2) = 100 100sin(2) = 100

Answer 1

the the v0 the initial velocity?

Answer 2

behold the most helpful tool on earth

Answer 3

The initial velocity is 36

Answer 4

\[h=\frac{ v _{0}^2 }{ 4.9\sin(\theta)\cos(\theta) }\]

Answer 5

does it look like that?

Answer 6

no the sin and cos are to the right. they are being multiplied, not divided

Answer 7

\[h=v _{0}^24.9\sin(\theta)\cos(\theta)\]

Answer 8

?

Answer 9

sorry. idk how to send pictures, but everything was right before just the sin and cos were being multiplied to the (v0^2)/4.9

Answer 10

so basicall ((vo^2)/4.9)sin(theta)cos(theta)

Answer 11

ok so v0=36m/s

Answer 12

the equation isnt right...

Answer 13

browser keeps acting up...

Answer 14

\[\frac{ v_{0}^2\sin(\theta)\cos(\theta) }{ 4.9 }\]

Answer 15

did you get it?

Answer 16

sin(2x)=2sin(x)cos(x)

so sin(x)cos(x)=(1/2)sin(2x)

Answer 17

ok

Answer 18

ok looks like

36^2/4.9 = 264.49

Answer 19

so we have

\[(264.49)(\frac{ 1 }{ 2 })(\sin(2x))=100\]

Answer 20

ohh ok

Answer 21

cause i think sin(2x)=2sin(x)cos(x)
and we have sin(x)cos(x)

so we divide the 2 out

Answer 22

id say im 80% sure on this one but its been awhile

Answer 23

i see. ok. thanks for the help

Answer 24

wait so if do i multiply the 264.49 by1/2?

Answer 25

ya i got something like 132.245

Answer 26

and the only answer chose is 132.12

Answer 27

so not sure on that

Answer 28

oh ok. thanks

Answer 29

http://www.wolframalpha.com/input/?i=sin%2830%29cos%2830%29

http://www.wolframalpha.com/input/?i=%281%2F2%29sin%2860%29

Answer 30

yep