Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

A piece of aluminum occupies a volume of 13.0 milliliters and weighs 52.9 grams. What is its density of the aluminum rounded to the nearest hundredth? Only enter numerical values, which can include a decimal point. @cwrw238 @SolomonZelman @hartnn

OpenStudy (anonymous):

density =mass/volume so density= 52.9/13=4.06mm3

OpenStudy (anonymous):

*gm/mm3

OpenStudy (anonymous):

so it would be 4.06 mm3?

OpenStudy (anonymous):

@zaibali.qasmi

OpenStudy (anonymous):

sorrey..its 4.06gm/mm3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!