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Chemistry 17 Online
OpenStudy (toxicsugar22):

calculate the value of of H3O+ FROM THE GIVEN [-OH] AND LABEL THE SOLUTIONAS ACIDIC OR BASIC a. 3.00*10^-4 M b. 2.66*10^-9 M

OpenStudy (toxicsugar22):

DO YOU UNDERSTAND THIS

OpenStudy (nincompoop):

yeah

OpenStudy (nincompoop):

use \[K_w\]

OpenStudy (nincompoop):

good?

OpenStudy (toxicsugar22):

CAN YOU PLEASE SHOW ME HOW TO DO THAT

OpenStudy (nincompoop):

what is the formula for water dissociation constant?

OpenStudy (toxicsugar22):

i really dont know

OpenStudy (toxicsugar22):

this is really bothering me as this is my first time doing this kind of problem

OpenStudy (toxicsugar22):

can you please help me untill we find the solutions

OpenStudy (toxicsugar22):

\[AXBY=XA+YB\]

OpenStudy (toxicsugar22):

IS THAT THE FORMUAL

OpenStudy (nincompoop):

nope

OpenStudy (nincompoop):

you can use that, but it doesn't really mean anything if you're not savvy in chem

OpenStudy (toxicsugar22):

i am not savvy in chem lol

OpenStudy (nincompoop):

http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch17/water.php there are sample problems in there in fact, before you are introduced into water dissociation constant, you will have to learn Ka and Kb first here's another one with example http://chemistry.tutorcircle.com/inorganic-chemistry/dissociation-constant.html#water-dissociation-constant

OpenStudy (toxicsugar22):

can you please help help help

OpenStudy (toxicsugar22):

is there an online calculaor that can do this for me

OpenStudy (nincompoop):

it's just a simple algebra really, there's nothing to teach. if you're having problem here, it means you do not meet to minimum math requirement to be in this class.

OpenStudy (toxicsugar22):

can you help me and so i will understand

OpenStudy (nincompoop):

start reading the contents in the links I provided

OpenStudy (toxicsugar22):

walk me through it step be step

OpenStudy (toxicsugar22):

it is just that chemistry makes me very anxious and go crazy

OpenStudy (toxicsugar22):

can you help me as i am visual learner

OpenStudy (toxicsugar22):

i will learn by having someone show it to me

OpenStudy (toxicsugar22):

like perhaps you

OpenStudy (nincompoop):

I have nothing to teach you that is different in the websites I provided

OpenStudy (toxicsugar22):

can you please show me how to get the solutions is what i want you to help me with

OpenStudy (toxicsugar22):

like perhaps do letter a for me and show me how to do it so i can do the next one

OpenStudy (nincompoop):

\[K_w = [H^+][OH^-] = 1 \times 10^{-14}\]

OpenStudy (nincompoop):

did you know that \[H_3O \] is the same as \[H^+\]

OpenStudy (nincompoop):

there is no kind of, either a yes or no, if not you are way behind your reading material to be doing this

OpenStudy (toxicsugar22):

i know

OpenStudy (toxicsugar22):

yes

OpenStudy (nincompoop):

then I cannot teach you water dissociation because you need to know a lot more before this concept

OpenStudy (toxicsugar22):

so i need to find out what Kw is

OpenStudy (nincompoop):

here's a textbook it is written so students can learn themselves http://finedrafts.com/files/CUNY/chemistry/General/Zumdahl%20etal/8th%20ed/ without a teacher's aid

OpenStudy (nincompoop):

you really need to change your study habits

OpenStudy (toxicsugar22):

we need to find what kw is right

OpenStudy (nincompoop):

you do, I don't check chapter 14 http://finedrafts.com/files/CUNY/chemistry/General/Zumdahl%20etal/8th%20ed/

OpenStudy (toxicsugar22):

is Ka = 3.70×10-5.

OpenStudy (nincompoop):

I don't know check chapter 14 of the Zumdahl Chemistry textbook it explains very well and easy to understand

OpenStudy (nincompoop):

yeah the textbook is VERY VISUAL I used it myself

OpenStudy (nincompoop):

if you dont like reading then stop wasting your time trying to get through chemistry

OpenStudy (nincompoop):

bye

OpenStudy (toxicsugar22):

do you undertand this problem

OpenStudy (anonymous):

Not really, sorry. I actually didnt even take Chem yet. just read a little of it.

OpenStudy (toxicsugar22):

okay if you know someone who is into chem please guide here. I desperalty need help

OpenStudy (anonymous):

alrighty. :)

OpenStudy (toxicsugar22):

do you know how to do this

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