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Mathematics 21 Online
OpenStudy (anonymous):

how to solve |13x| > -5????

OpenStudy (babalooo):

what you're trying to do is isolate the value x. treat the inequality like a equal sign and only change the sign when you are dividing by negative value. remember it's absolute sign so it can be both 13x and -13x for postive and negative values

OpenStudy (anonymous):

I'm really lost like how do I even start?

OpenStudy (babalooo):

so it's |13x| > -5 because it's in absolute brackets, then it can be 2 equations 13x > -5 if it is 13x=-5, do you know how to solve? and -13x>-5 if it is -13x = -5 do you know how to solve?

OpenStudy (babalooo):

p.s. treating it as = sign does not necessarily give you the correct answer for inequaility.. I'm just leading you to the solution.

OpenStudy (anonymous):

okay I think its x< 5/13 or x> -5/13

OpenStudy (anonymous):

Am I right?

OpenStudy (babalooo):

nope. your signs are wrong. inequality change ONLY when you perform multiplication/division of a negative value for 13x >-5, you divide by positive 13 x>-5/13 and for -13x<-5, you divide by negative so sign switch x>5/13. does it make sense

OpenStudy (anonymous):

my answer choices don't have what your explaining :(

OpenStudy (xapproachesinfinity):

my friend when you have |x|>a, a is negative number the solution is all real numbers, because any number you throw in for x will satisfy the equation. that is just the definition of absolute value

OpenStudy (xapproachesinfinity):

|x|>=0 always true so solution is the set of real numbers |x|<a, a positive solution is -a<x<a |x|>a, a positive solution is x>a or x<-a |x|<a, a negative no solutions absolute values is always greater than or equal zero

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