Question

How to solve for t in d=16t^2

Answer 1

\[d=16t^{2}\]
\[\frac{ d }{ 16 }=t^{2}\]
\[\sqrt{\frac{ d }{ 16 }}=\frac{ \sqrt{d} }{ 4 }\]

Answer 2

i dont understand the whole sq root thing you did above @charliealbert

Answer 3

chaeliealbert is correct, sorry about messing up above, swapped order of simplification

Answer 4

Ohh
\[\frac{ \sqrt{d} }{ 4 }=t\]

Answer 5

I used the square root in both sides to make t to the first power

Answer 6

oh okay thx :) @charliealbert

Answer 7

No problem